下表显示了二元运算符，其目的列表。
| 函数名称 | 运算符 | 目的 |
|---|---|---|
| opBinary | + | 加法 |
| opBinary | - | 减法 |
| opBinary | * | 乘法 |
| opBinary | / | 除法 |
| opBinary | % | 求余 |
| opBinary | ^^ | 幂 |
| opBinary | & | 按位与 |
| opBinary | | | 按位或 |
| opBinary | ^ | 按位异或 |
| opBinary | << | 左移 |
| opBinary | >> | 右移 |
| opBinary | >>> | 逻辑右移 |
| opBinary | ~ | 串连 |
| opBinary | in | 是否包含 |
一个例子如下，解释如何重载一个二元运算符。
| import std.stdio; |
| class Box |
| { |
| public: |
| double getVolume() |
| { |
| return length * breadth * height; |
| } |
| void setLength( double len ) |
| { |
| length = len; |
| } |
| void setBreadth( double bre ) |
| { |
| breadth = bre; |
| } |
| void setHeight( double hei ) |
| { |
| height = hei; |
| } |
| Box opBinary(string op)(Box b) |
| { |
| if(op == "+") |
| { |
| Box box = new Box(); |
| box.length = this.length + b.length; |
| box.breadth = this.breadth + b.breadth; |
| box.height = this.height + b.height; |
| return box; |
| } |
| } |
| private: |
| double length; // Length of a box |
| double breadth; // Breadth of a box |
| double height; // Height of a box |
| }; |
| // Main function for the program |
| void main( ) |
| { |
| Box box1 = new Box(); // Declare Box1 of type Box |
| Box box2 = new Box(); // Declare Box2 of type Box |
| Box box3 = new Box(); // Declare Box3 of type Box |
| double volume = 0.0; // Store the volume of a box here |
| // box 1 specification |
| box1.setLength(6.0); |
| box1.setBreadth(7.0); |
| box1.setHeight(5.0); |
| // box 2 specification |
| box2.setLength(12.0); |
| box2.setBreadth(13.0); |
| box2.setHeight(10.0); |
| // volume of box 1 |
| volume = box1.getVolume(); |
| writeln("Volume of Box1 : ", volume); |
| // volume of box 2 |
| volume = box2.getVolume(); |
| writeln("Volume of Box2 : ", volume); |
| // Add two object as follows: |
| box3 = box1 + box2; |
| // volume of box 3 |
| volume = box3.getVolume(); |
| writeln("Volume of Box3 : ", volume); |
| } |
让我们编译和运行上面的程序，这将产生以下结果：
Volume of Box1 : 210 Volume of Box2 : 1560 Volume of Box3 : 5400
