COUNT(column_name) 函数返回指定列的值的数目(NULL 不计入):
SELECT COUNT(column_name) FROM table_name;
COUNT(*) 函数返回表中的记录数:
SELECT COUNT(*) FROM table_name;
COUNT(DISTINCT column_name) 函数返回指定列的不同值的数目:
SELECT COUNT(DISTINCT column_name) FROM table_name;
注释:COUNT(DISTINCT) 适用于 ORACLE 和 Microsoft SQL Server,但是无法用于 Microsoft Access。
在本教程中,我们将使用 web3.xin 样本数据库。
下面是选自 "access_log" 表的数据:
+-----+---------+-------+------------+ | aid | site_id | count | date | +-----+---------+-------+------------+ | 1 | 1 | 45 | 2016-05-10 | | 2 | 3 | 100 | 2016-05-13 | | 3 | 1 | 230 | 2016-05-14 | | 4 | 2 | 10 | 2016-05-14 | | 5 | 5 | 205 | 2016-05-14 | | 6 | 4 | 13 | 2016-05-15 | | 7 | 3 | 220 | 2016-05-15 | | 8 | 5 | 545 | 2016-05-16 | | 9 | 3 | 201 | 2016-05-17 | +-----+---------+-------+------------+
下面的 SQL 语句计算 "access_log" 表中 "site_id"=3 的总访问量:
SELECT COUNT(count) AS nums FROM access_log WHERE site_id=3;
下面的 SQL 语句计算 "access_log" 表中总记录数:
SELECT COUNT(*) AS nums FROM access_log;执行以上 SQL 输出结果如下:
mysql> select count(*) as nums from access_log; +------+ | nums | +------+ | 9 | +------+ 1 row in set (0.00 sec)
下面的 SQL 语句计算 "access_log" 表中不同 site_id 的记录数:
SELECT COUNT(DISTINCT site_id) AS nums FROM access_log;执行以上 SQL 输出结果如下:
mysql> select count(distinct site_id) as nums from access_log; +------+ | nums | +------+ | 5 | +------+ 1 row in set (0.00 sec)