LAST() 函数返回指定的列中最后一个记录的值。
SELECT LAST(column_name) FROM table_name;
注释：只有 MS Access 支持 LAST() 函数。
SELECT TOP 1 column_name FROM table_name ORDER BY column_name DESC;
SELECT TOP 1 name FROM Websites ORDER BY id DESC;
SELECT column_name FROM table_name ORDER BY column_name DESC LIMIT 1;
SELECT name FROM Websites ORDER BY id DESC LIMIT 1;
SELECT column_name FROM table_name ORDER BY column_name DESC WHERE ROWNUM <=1;
SELECT name FROM Websites ORDER BY id DESC WHERE ROWNUM <=1;
在本教程中，我们将使用 web3.xin 样本数据库。
下面是选自 "Websites" 表的数据：
+----+--------------+---------------------------+-------+---------+ | id | name | url | alexa | country | +----+--------------+---------------------------+-------+---------+ | 1 | Google | https://www.google.cm/ | 1 | USA | | 2 | 淘宝 | https://www.taobao.com/ | 13 | CN | | 3 | 芝麻教程 | http://www.web3.xin/ | 4689 | CN | | 4 | 微博 | http://weibo.com/ | 20 | CN | | 5 | Facebook | https://www.facebook.com/ | 3 | USA | | 6 | 百度 | https://www.baidu.com/ | 4 | CN | | 7 | stackoverflow | http://stackoverflow.com/ | 0 | IND | +----+---------------+---------------------------+-------+---------+
下面的 SQL 语句选取 "Websites" 表的 "name" 列中最后一个记录的值：
SELECT name FROM Websites ORDER BY id DESC LIMIT 1;执行以上 SQL 结果如下所示：
mysql> select name from websites order by id desc limit 1; +---------------+ | name | +---------------+ | stackoverflow | +---------------+ 1 row in set (0.00 sec)
